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7v^2+8v-80=0
a = 7; b = 8; c = -80;
Δ = b2-4ac
Δ = 82-4·7·(-80)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-48}{2*7}=\frac{-56}{14} =-4 $$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+48}{2*7}=\frac{40}{14} =2+6/7 $
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